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1. What is the perimeter of a triangle whose sides are 2x²+ 7 cm, x²-2 cm and 4x²+ 4cm?​

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Answer:

The perimeter of the given triangle is equal to (7x² + 9) cm

Step-by-step explanation:

SOLUTION

P = (2x²+7cm) + (x²-2cm) + (4x²+4cm)? ; rearrange the solution by putting the like-terms side-by-side

P = (2x² + x² + 4x²) + [7 + (-2) + 4] ; then add

P = (7x² + 9) cm

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