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Learning Task C:
Solve the problem:
Mr. Tony bought 4 kg of soya beans (x) and 3 kg of brown sugar (y) and paid of not more than
Php 463.00. If a kilogram of brown sugar is Php 45.00, then how much is the cost of a kilogram of soya beans?

Represenration:


Translation (Inequality):


Solution:


Answer:​

Sagot :

KUYAENGRGO

In the given problem, apply your knowledge in algebraic expression specially in solving unknown variables of linear equation system.

Given:

4 kg of soya beans, and (x) stands for cost each kg

3 kg of brown sugar, and (y) stands for cost each kg

a kilogram of brown sugar is Php 45.00

paid of not more than Php 463.00.

Solution

Total cost ≥ (Cost of soya beans)(kg of soya beans) + (cost of brown sugar)(kg of brown sugar)

463 ≥ (x)(4) + 45(3)

463 ≥ 4x + 135

463 - 135 ≥ 4x

328 ≥ 4x

4x ≥ 328/4

x ≥ 82

Answer: Php. 82.00

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