determine the discriminant and nature of roots of each quadratic equation.
a)x²– 6x + 9=0
b)x² – 4x + 3=0
c)x² – 7x – 4=0
d)2x² + 3x + 5=0

help me please..​


Sagot :

Answer:

> The discriminants <

a) 0

b) 4

c) 65

d) -31

> Nature of roots <

a) real,equal and rational

b) real, distinct and rational

c) real, distinct and irrational

d) imaginary

Step-by-step explanation:

Formula:

  • b² - 4ac

Solution:

a) x² - 6x + 9 = 0

  • a = 1 b = -6 c = 9
  • -6² - 4 (1) (9)
  • 36 -36
  • 0

b) x² - 4x + 3 = 0

  • a = 1 b = -4 c = 3
  • -4² - 4 (1) (3)
  • 16 - 12
  • 4

c) x² - 7x - 4 = 0

  • a = 1 b = -7 c = -4
  • -7² - 4 (1) (-4)
  • 49 + 16
  • 65

d) 2x² + 3x + 5 = 0

  • a = 2 b = 3 c = 5
  • 3² - 4 (2) (5)
  • 9 - 40
  • -31