QUESTION:
In (x+3) (x+4) = 0, what is that value of A, B and C?
SOLUTION:
Use the FOIL method to expand the expression.
[tex](x + 3)( x + 4) \\ = {x}^{2} + 4x + 3x + 12 \\ = {x}^{2} + 7x + 12[/tex]
Equal the expression to zero, and identify the value of a, b, and c.
[tex] {x}^{2} + 7x + 12 = 0 \\ a = 1, \: b = 7, \: c = 12[/tex]
ANSWER:
The value of a is 1.
The value of b is 7.
The value of c is 12.
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