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2. A gas inside a container has an initial volume of 0.5 L at 10.0 °C. If the temperature is increased to 50.0 °C, what will be the new volume​

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Answer:

V₂ = T₂ ₓ Vi/Ti

    = 323.15 k (0.5 L ÷ 283.15 k)

    = 0.57 L (if you didn't round off*) or 0.58 L (if you round off*)

Explanation:

Δ the i in the formula serves as initial

Δ you can convert celsius to kelvin by adding 273.15

Δ *the number that you'll round off is the division of initial volume(Vi)

    and initial time(Ti)

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