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One solution is 70% chlorinated and another one is 40% chlorinated. How much of each solution is needed to make a 200-gallon solution that has 55% chlorine?.

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# Let x be the amount of 70% chlorinated solution and y be the amount of 40% chlorinated solution.

# Then,0.7x + 0.4y = 0.55(x + y)

# 0.7x + 0.4y = 0.55x + 0.55y

# 0.3x = 0.15y

# x = 0.5y

# x + y = 200

# 0.5y + y = 200

# 1.5y = 200

# y = 200/1.5

# y = 133.33

# x = 0.5y

# x = 0.5(133.33)

# x = 66.67

# So, 66.67 gallons of 70% chlorinated solution and 133.33 gallons of 40% chlorinated solution are needed to make a 200-gallon solution that has 55% chlorine.

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