A 31L gas has a pressure of 912torr and a temperature of 87oC. How many moles of gas does it contain?​

Sagot :

Answer:

0.12 mol

Explanation:

912 torr — 912•1atm/760 torr = 1.2 atm -P

87°C — 87+273 = 360 K -T

31 L - V

PV/ RT = nRT/RT cancell n= PV/RT

substitute

n= (1.2 atm)(31L) / (0.8206 L• atm/mol•K)

n= 37. 2/295.42 mol

n= 0.12 mol

Go Educations: Other Questions