JAY03CEREDONGO JAY03CEREDONGO

Math

Answered

in a 4- digit combination lock, how many possible codes are there if no digits in the lock are repeated??? with solution pls

Sagot :

TTJMR34563421GO TTJMR34563421GO

Permutation Problem
P(10, 4) = 10!/(10 - 4)!
P(10, 4) = 3628800/(6)!
P(10, 4) = 3628800/720
P(10, 4) = 5040

There are 5040 possible codes

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