Answer:
B. 1/4
Step-by-step explanation:
Sample space for total number of possible outcomes
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
Total number of outcomes = 36
Favorable outcomes for sum greater than 10 are
(5,6), (6,5), (6,6)
Number of favorable outcomes = 3
Favorable outcomes for sum less than 5 are
(1,1), (1,2), (1,3), (2,1), (2,2), (3,1)
Number of favorable outcomes = 6
Hence, the probability of obtaining a sum greater than 10 or sum less than 5 = [tex]\frac{3+6}{36} = \frac{9}{36} = \frac{1}{4}[/tex]
