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14. The reaction of aluminum with iodine produces aluminum iodide. How many moles of AII 3(s) , are produced by the reaction of 6.0 moles of aluminum according to the following equation; 2Al (s) +3I 2(s) AII 3(s)

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Answer:

Solution:

Step 1: Determine the mole ratio needed.

mole ratio = 2 mol Al(OH)₃ : 1 mol Al₂O₃

Step 2: Calculate the number of moles of Al(OH)₃ produced using the mole ratio.

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Explanation:

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