Answer:
[tex] \huge \tt \blue { \underline{Kasagutan: }}[/tex]
[tex]\large\tt\green{1. \: 3} \\ \large\tt\green{2. \: -5} \\ \large\tt\green{3. \: 2}[/tex]
[tex] \huge \tt \blue { \underline{Solution: }}[/tex]
[tex]\large\tt{1. \: f(x)=3x+10} \\ \large\tt\green{f(x)=3} \\ \large\tt{2. f(x)=2-5x } \large\tt\green{\:=-5}[/tex]
[tex] \tt \red{lets \: say \: i \: have \:the \: tangent} \\ \tt \red{and \: y = f(x) \: is \: the \: derivative} \\ \tt \red{equation. \: the \: slope \: K \: can \: be} \\ \tt \red{solved \: by \: K =f(.c) }[/tex]
[tex] \large \tt{3. \: f(x) = \frac{d}{dx} ( {x}^{2} + 9)}[/tex]
[tex]\large \tt{f(x) = \frac{d}{dx} ( {x}^{2} ) + \frac{d}{dx} (9)}[/tex]
[tex] \large \tt{f(x) = 2x + \frac{d}{dx} (9)}[/tex]
[tex] \large \tt\green{f(x) = 2x}[/tex]
