What is the missing side between the congruent triangles?


Sagot :

A triangle is uniquely defined by any one of these conditions:

SSS (knowing all 3 side lengths)

SAS (knowing 2 sides and the angle between them)

ASA (knowing 2 angles and the length of the side between them)

AAS (equivalent to ASA, since if we know 2 angles, we can compute the 3rd)

To show two triangles are congruent, we need to show that they have enough equivalent corresponding sides/angles, so that one of the above options is satisfied.

For this pair of triangles, we see that

¯¯¯¯¯¯

L

Y

¯¯¯¯¯¯

U

G

,

since they both have length 7.2.

Next, both triangles have a side of length 6, those being

¯¯¯¯¯¯

Y

F

and

¯¯¯¯¯¯

G

B

,

meaning

¯¯¯¯¯¯

Y

F

¯¯¯¯¯¯

G

B

.

Finally,

m

Y

=

56

,

and so is

m

G

.

Thus,

Y

G

.

Since all three of these congruent values appear in the same order in each triangle (i.e. in SAS order), this shows

L

Y

F

U

G

B

.

It is important to list the vertices in this order, because it's the order in which they match up (or correspond). That is:

L

goes with

U

,

Y

goes with

G

, and

F

goes with

B

.

To determine the missing values, we look at the corresponding value in the other triangle. For instance,

x

=

B

U

,

and since

¯¯¯¯¯¯

B

U

¯¯¯¯¯¯

F

L

, and

F

L

=

6.3

,

that gives us

x

=

6.3

.

Similarly,

z

=

m

B

=

m

F

=

72

,

and

y

=

m

U

=

m

L

=

52

.