Answered

How many moles of KI are present in 0.85 L of a 0.55 M KI solution?

Sagot :

NAUNLUDMARYANGO

Answer:

Molarity=n/V

0.55=n/0.85

n=0.55×0.85

n=0.4675 moles

Therefore,there are 0.4675 moles of KI of 0.85L of a 0.55 M KI solution.

Explanation:

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