Answered

The area of a rectangle is 18a3b2c and its width is 9ab2. Find its length.

Sagot :

MELODYFLORES683GO

Answer:

Rectangle

Solve for length

l=2

w Width

9

A Area

18

Using the formula

A=wl

Solving forl

l=A

w=18

9=2

PURPLEDADDYGO

A=LW

18a³b²c = L•9ab²

[tex] \frac{18 {a}^{3} {b}^{2} c}{9a {b}^{2} } = \frac{l \times 9a {b}^{2}}{9a {b}^{2}} [/tex]

2a²c = L

Therefore, L = 2a²c

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