JESSIELINECALUNSAGGO
Answered

1. What volume of alcohol is required to prepare 250ml of a 10% by volume solution?​

Sagot :

MATTHEWECALDREGO

Answer:

Step-by-step explanation:

Let the volume of alcohol taken = x mL.

Volume percent = Volume of alcohol/ volume of solution* 100.

Or 60= x/ 250 * 100 or X (i.e. volume of ethanol mixed).

= 60*250/100

= 150 mL.

Ꭲᕼᗴᖇᗴᖴᝪᖇᗴ ᐯᝪᏞᑌᗰᗴ ᝪᖴ ᗯᗩᎢᗴᖇ ᗰᏆ᙭ᗴᗞ = 250- 150 = 100ᗰᏞ

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