BLOOMINGKIYAGO
Answered

How many different nine-digit numbers can be written using the following digits: 2,2,2,7,7,8,8,8, and 9?​

Sagot :

KATHERINEOSTANGO

Answer:

5040 distinguishable permutations

Step-by-step explanation:

Distinguishable permutation formula

P = n! / p!q!r!s!

Let p q r s be the repeated numbers

P = 9! / 3!2!3!1!

P = 9×8×7×6×5×4×3×2×1 / 3×2×1×2×1×3×2×1×1

P = 9×8×7×6×5×4×3×2×1 / 6×3×2×1×2

cancel out

P = 9×4×7×5×4

P = 5040

████████▀▀▀████

████████────▀██

████████──█▄──█

███▀▀▀██──█████

█▀──▄▄██──█████

█──█████──█████

█▄──▀▀▀──▄█████

███▄▄▄▄▄███████

Go Educations: Other Questions