Answer:
Let
x=# of chickens
y=# of goats
Each chicken and goat has 1 head.
Each chicken has 2 legs. Each goat has 4 legs.
This results in the following system of equations:
x+y=43
2x+4y=108
Solve for x in first equation:
x=43-y
Substitute x in other equation to get:
2x+4y=108
2(43-y)+4y=108
86-2y+4y=108
2y=22
y=11
x+y=43
x+11=43
x=32
Therefore, 11 goats and 32 chickens
