Answer:
so the awnser is REGULAR
Step-by-step explanation:
Let ABCDEFGH. is a regular octagon whose. center is O. In isosceles ∆
OAB. OA=OB , AB= 5 cm. and angle AOB = 45°. draw OP perpendicular
on AB
In right triangle APO :-
AP=AB/2=5/2=2.5. cm. and angle AOP=45/2=22.5°
AP/OP=tan 22.5°
2.5/OP = 0.4142
OP =2.5/0.4142 = 6.0357 cms.
Area of triangle OAB = ( AB ×OP)/2 = ( 5 ×6.0357)/2
Area of regular octagon ABCDEFGH =8×area of ∆ OAB.
=8×(5×6.0357)/2
=20×6.0357
= 120.714O sq. cm. Answer
