Answered

Find the area of a rectangle whose length is[tex](4x^{2} -6x+9)[/tex] inches and width of (2x+3) inches

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MAXIMORYKEIGO

Answer:

8x³ + 27

Step-by-step explanation:

Formula: [tex]\tt{Area \: = Length \times Width}[/tex]

  • Solve it using distributive property

A = l × w

A = (4x² - 6x + 9)(2x + 3)

A = 4x²(2x + 3) - 6x(2x + 3) + 9(2x + 3)

A = 8x³ + 12x² - 12x² - 18x + 18x + 27

A = 8x³ + 27

Therefore, 8x³ + 27 is the area of a rectangle.

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