Answer:
the perimeter is 40
first add the sides
[tex]x + 8 \\ 3x + 4 \\ 2x + 8 \\ - - - - - - - \\ 6x + 20[/tex]
then equate 6x+20 to 0
and find x
[tex]6x + 20 = 0 \\ x = \frac{10}{3} [/tex]
then substitute 10/3 to all x
[tex]x + 8 \\ = \frac{10}{3}+ 8 \\ = \frac{34}{3} [/tex]
[tex]3x + 4 \\ = 3( \frac{10}{3} ) + 4 \\ = 14 \\ or \: \frac{42}{3} [/tex]
[tex]2x + 8 \\ = 2( \frac{10}{3} ) + 8 \\ = \frac{44}{3} [/tex]
then add
[tex] \frac{34}{3} + \frac{42}{3} + \frac{44}{3} \\ = \frac{120}{3} \\ = 40[/tex]
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