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Suppose w varies directly as x and inversely as the square of y.When x = 8 when y = 4 and w = 18,what is the value of w if x = 4 and y = 6? (Hint: the equation is w = kx/y²)

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Answer:

w = kx/y²

18 = k(8)/(4)²

18 = 8k/16

18 = 8k/16 ÷ 8/8

18 = k/2

18 × 2 = k/2 × 2

36 = k

w = 36(4)/(6)²

= 144/36

= 144/36 ÷ 36/36

w = 4

MIRMIR1578GO

w =x

y²

w = k x

y²

w = k x 8

(4)²

k = 36

when x = 4;y = 6

w = K x X

y²

= 36 x 4

62

W = 4

Step-by-step explanation:

hope it can help you

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