In figure at the right, quadrilateral LOST is inscribed in OU, if m<LTS = 81° and m<TSO = 96°, find the measure of the following:

Solution:
The sum of the measure of the opposite angles of the quadrilateral are supplementary angles, which equals 180°.
If ∠TSO = 96°, then we must find the measure of ∠TLO.
∠TSO + ∠TLO = 180°
96 + ∠TLO = 180
∠TLO = 180 - 96
∠TLO = 84°
Solution:
The sum of the measure of the opposite angles of the quadrilateral are supplementary angles, which equals 180°.
If ∠LTS = 81°, then we must find the measure of ∠LOS.
∠LTS + ∠LOS = 180°
81 + ∠LOS = 180°
∠LOS = 180 - 81
∠LOS = 99°
Solution:
If ∠LOS = 99, then arc LTS is doubled the measure of ∠LOS.
Arc LTS = 2 ∠LOS
Arc LTS = 2 ( 99)
Arc LTS = 198°
Solution:
If ∠TLO = 84°, then Arc TSO is doubled to the measure of ∠TLO.
Arc TSO = 2 ∠TLO
Arc TSO = 2 (84)
Arc TSO = 168°