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if y varies directly as x and inversely as z and y = 22 when x = 4 and z = 6 find the value of k​

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[tex]\large{\mathcal{SOLUTION:}}[/tex]

Equation: y = kx/z

[tex] \\ [/tex]

Given: y = 22 , x = 4 , z = 6

Solving for the value of k

  • y = kx/z
  • 22 = k(4)/6
  • 22×6 = 4k
  • 132 = 4k
  • 132/4 = k
  • 33 = k

Therefore , the value of k is 33

[tex] \\ [/tex]

[tex]\large{\mathcal{ANSWER:}}[/tex]

  • k = 33

[tex] \\ [/tex]

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