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Math

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Mr.romero organized the mathematics club of 16 girls and 36 boys.what us the biggest number of members each group can have which have an equal number of girls and boys.what is asked?

Sagot :

ANAMARIEMATULINGO ANAMARIEMATULINGO

Answer:

Solve:

GCF of 16 and 36 is-

16= 2×2×2×2

36= 2×2×9

Since GCF= 2x2=4

The biggest number is 4 for each group can have which could have an equal numbers of girls and boys.

Step-by-step explanation:

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