An apple fell down from a tree. The work done by the gravity of the apple is equal to 3.42 J. If the apple is equal to 0.10 kg, how far did the apple fall down?

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The height or position of an object is given by

[tex]\boxed{h = \frac{PE}{mg}}[/tex]

where:

h = height

PE = potential energy

g = acceleration due to gravity = 9.8 m/s²

h = height

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for the height

[tex]h = \dfrac{PE}{mg}[/tex]

[tex]h = \dfrac{\text{3.42 J}}{(\text{0.10 kg})(\text{9.8 m/}\text{s}^{2})}[/tex]

[tex]\boxed{h = \text{3.49 m}}[/tex]

Therefore, the apple falls 3.49 m down the tree.

[tex]\\[/tex]

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