Answer:
To solve an n-dimensional linear system Ax = b we factor A as a product of two triangular matrices, A = LU: L is lower triangular, L = [li,j], li,j = 0 if j > i and li,i = 1. U is upper triangular U = [ui,j], ui,j = 0 if i > j. Forward substitution: Ly = b.
Explanation:
In the mathematical discipline of linear algebra, a triangular matrix is a special kind of square matrix. A square matrix is called lower triangular if all the entries above the main diagonal are zero. ... Because matrix equations with triangular matrices are easier to solve, they are very important in numerical analysis.
