Answer:
Max area: 30 * 10 = 300 sq/meters
Step-by-step explanation:
From the information given, we will need 3 widths and 1 length
L + 3W = 60
L = (60-3W)
Area
A = L*W
Replace L with (60-3W)
A = W(60-3W)
A = -3W^2 + 60W
max area occurs at the axis of symmetry, (x=-b/(2a)), in this equation a=-3, b=60
W = -60/2x(-3)
W = + 10 meters is the width
Find the Length
60 - 3(10) = 30 meters is the length
Max area: 30 * 10 = 300 sq/meters
