When 20.0 g of Iron is heated from 10.0ºC to 20.0ºC, 25.0 cal of heat is absorbed. What is the specific heat of Iron

Sagot :

Answer:

4.0 g/ml

Step-by-step explanation:

Volume_XVolume

X

= water displaced by X

Water displaced by object X = Final fluid level - Original fluid level

Water displaced by object X = 90 ml - 65 ml = 25 ml

Volume_{X} = 25 mlVolume

X

=25ml

Density of rock:

100 grams => 25 ml

x grams => 1 ml

Cross multiply

x*25 = 1*100

25x = 100

25x/25 = 100/25

x = 4

Density of object X = 4 g per 1 ml = 4.0 g/ml