3Mg(s) + 2FeCl3(s) → 3MgCl2(s) + 2Fe(s)

Sagot :

Answer:

A mixture of 41.0 g of magnesium (MM = 24.31 g/mol) and 175 g of iron(III) chloride (MM = 162.2 g/mol) is allowed to react. Identify the limiting reactant, and determine the the mass of the excess reactant present in the vessel when the reaction is complete.