finding of value of sin 5 radiant over 3​

Sagot :

Answer:

[tex]0 for \: sin \: \frac{sin \: (5 \pi) ?}{3} and - \sqrt{ \frac{3}{2} } \: for \: sin \: ( \frac{5}{3} )[/tex]

[tex]sin \: ( \frac{5\pi}{3} ) \: = \frac{0}{3} = 0 \\ as \: sin \: ( \frac{5\pi}{3} ) \\ sin \: ( \frac{5\pi}{3} ) = sin \: ( \frac{6\pi - \pi}{3} ) \\ = sin \: (2\pi - \frac{\pi}{3} ) \\ = - sin \: ( \frac{\pi}{3)} \\ = - \sqrt{ \frac{3}{2} } [/tex]

HOPE IT HELPS, HAVE A GOOD DAY.