Let x be the hypotenuse
according to the question , one side is 4 less than the hypotenuse
so we will represent it by x-4
the other side was 2 decimeters more than the other one. which we can represent it as
(x-4) + 2
Next is we use pythagorean theorem
which is a^2 + b^2 = c^2 where a and b are sides and c was the hypotenuse
next is apply the pythagorean theorem with the solutions we got above.
(x-4)^2 + (x - 4 + 2)^2 = x^2
(x-4)^2 + (x-2)^2 = x^2
x^2 -8x + 16 + x^2 -4x + 4 = x^2
x^2 -12x + 20 = 0
Factor
(x-10)(x-2)
x= 10
x= 2
Since the one side says that it was "4 less than the hypotenuse" long , we cannot use the 2 as we will get a negative value for it , so we will use 10
hypotenuse = x = 10
Side = x - 4 = 10 - 4 = 6
Side = x - 2 = 10 - 2 = 8
Therefore we got 10,8,6
