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Determine the quadratic function y=ax2+bx+c given the vertex (1,-2) and y-intercept (0,-1)

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RSQUARED42GO

Answer:

y = (x - 1)² - 2

y = x² - 2x - 1

Solution:

y = (x - h)² + k given the vertex (h,k)

That's all. Hope it helps.

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