Step-by-step explanation:
2/(x-2) = 4/(x+1) + 1
2/(x-2) = ( 4 + x + 1) / (x + 1)
2/(x-2) = (x+5)/(x+1)
2/(x-2) - (x+5)/(x+1) = 0
[2(x+1) - (x+5)(x-2)] /[(x-2)(x+1)] = 0
(2x + 2 - x^2 -3x + 10 )/ [(x-2)(x+1)] =0
(-x^2 - x + 12)/ [(x-2)(x+1)]
-(x+4)(x-3) / [(x-2)(x+1)] = 0
Dont mind the denominator as you will get undefined/indeterminate answers so focus on the numerator
(x+4)(x-3) = 0
x= - 4
x = 3
