the area of a rectangle is 65 m squared and the length is 3 m less than twice the width​

Sagot :

Step-by-step explanation:

[tex]l \: = 2w \: - \: 3 \\ a \: = \: l \: x \: w \\ 65 \: = (2w \: - \: 3)(w) \\ 65 = 2w {}^{2} - 3w \\ 0 = 2w {}^{2} - 3w - 65 \\ 0 = (2w \: - 13)(w + 5) \\ w = 13 \: or \: 2 \\ w = 5 \\ use \: the \: positive \: number \\ w = 13 \: or \: 2 \\ l = 2(13or \: 2) - 3 = 13 - 3 = 10 \\ checking \\ 65 = 10 \: x13or \: 2 \\ 65 = 130or \: 2 \\ 65 = 65 \: correct[/tex]