factor the following polynomial 2x⁴+x³-19x²-9x+9​

Sagot :

Answer:

(x+1)(2x-1)(x-3)(x+3)

Step-by-step explanation:

2x⁴+x³-19x²-9x+9

write x³ as a difference

2x⁴+2x³-x³-19x²-9x+9

write -19x² as a difference

2x⁴+2x³-x³-x²-18x²-9x+9

write -9x as a sum

2x⁴+2x³-x³-x²-18x²-18x²+9x+9

factor out 2x³ from the expression

2x³(x+1)-x³-x²-18x²-18x+9x+9

factor out -x² from the expression

2x³(x+1)-x²(x+1)-18x²-18x+9x+9

factor out -18x from the expression

2x³(x+1)-x²(x+1)-18x(x+1)+9x+9

factor out 9 from the expression

2x³(x+1)-x²(x-1)-18x(x+1)+9(x+1)

factor out x+1 from the expression

(x+1)(2x³-x²-18x+9)

factor out x² from the expression

(x+1)(x²(2x-1)-18x+9)

factor out -9 from the expression

(x+1)(x²(2x-1)-9(2x-1)

factor out 2x-1 from the expression

(x+1)(2x-1)(x²-9)

use a²-b²=(a-b)(a+b) to factor the expression

(x+1)(2x-1)(x-3)(x+3)