Answer:
Given. 2x²+13x+20=0
Step-by-step explanation:
Use the standard form, ax²+bx+c=0, to find the coefficients of our equation,
2x²+13x+20=0
a= 1
b= 13
c= 20
[tex] x = - b+ \sqrt{b ^{2} - 4ac} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2a[/tex]
[tex]x = - 1. - 13 + \sqrt{ - 13 ^{2} - 4.2.20} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2.2[/tex]
Simplify exponents and square roots
[tex]x = - 1. - 13 + \sqrt{169 - 4.2.20} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2.2[/tex]
Perform any multiplication or division, from left to right:
[tex]x = - 1. - 13 + \sqrt{169 - 8.20} \\ 2.2[/tex]
[tex]x = - 1. - 13 + \sqrt{169 - 160} \\ 2.2[/tex]
[tex]x = 1. - 13 + \sqrt{9} \\ 2.2[/tex]
[tex]x = 1. - 13 + \sqrt{9} \\ 4[/tex]
[tex] \times = 13 + \sqrt{9} \\ 4[/tex]
to get the result:
[tex]×=13+ \sqrt{9 } \\ 4
[/tex]
