VINCENZO143GO
Answered

pa help pa help pa help pa help pa help pa help pa help pa help

find the 8th geometric sequence which has for its 3rd and 6th terms are 1 and -64
a.-1024
b 2048
c.4096
d.3076​

Sagot :

KINZYITCHGO

Answer:

A

Step-by-step explanation:

a+2d = 7

a+5d =36

subtract them:

3d = 29

d = 29/3

then a + 58/3 = 7

3a + 58 = 21

a = -37/3

term(8) = a + 7d

= -37/3 + 7(29/3) = 166/3

check:

-37/3 , -8/3 , 7 , 50/3 , 79/3 , 36, 137/3, 166/3, ..

Go Educations: Other Questions