what is the percent if 10.0grams of copper is added to enough zinc to produce 110grams of an alloy?​

Sagot :

Answer:

%(m/m) = 9.09%

Explanation:

%(m/m) = (mass solute / mass solution) × 100

%(m/m) = (10.0 g / 110 g) × 100

%(m/m) = 9.09%