Sagot :
Answer:
Correct option is
A
{1,2,3}
f(x)=7−xPx−3
(1) 7−x>0
x<7
(2) x−3≥0
x≥3
(3) (x−3)≤(7−2)
x+x+≤7+3
2x≤10
x≤5
So, x=3,4,5
Range of f(x)=4P0,3P,2P2
=4!4!,2!3!,0!2!
=1,3,2
Range of f(x)={1,2,3}
Step-by-step explanation:
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