How much electric current flow through a lamp with resistance 100 when it is connected to a 200-V outlet?
Given:
Find:
Solution:​


Sagot :

power = volt x current

so current = power / volt

current = 100/220 = 0.45 A

this is for pure resistive load with power factor equal 1 such as normal lamp in case of AC (alternaing current )

100w is power, and from power(P) equal to voltage(V) multipied by ampere(A)

Therefore 100=220*A

A=100/220

A=0.4545Ampres

Current is simply the rate of flow of charges whereas voltage can be simply defined as the energy that pushes the charges around a circuit.

Therefore,

V=work/charge=W/q

Hence, W=V×q

I=q/t

Power (P)= rate of work done=W/t=V×q/t=VI

Hence, I=P/V=100/220=5/11

Therefore, the current of that lamp is 5/11 which is approximately 0.45Amps.

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Answer:

Given :

    R=100 ohms

    V = 200 volts

    C= ?

Solution:

I = V / R (this is the formula)

= 200V / 100ohms  

= 2A