[tex]Question & Solution:[/tex]
A 20-liter tank is to be filled with water by repeated pouring from a can which holds 2 and 1/2 liters.How many times pouring are needed to fill the tank?
This calls for a division senetence
- [tex]20 \div 2\frac{1}{2} = 20 \div \frac{5}{2} [/tex]Changed mixed fraction to improper fraction
- [tex] = \frac{20}{1} o \frac{2}{5} [/tex]Multiply the dividend to the multiplicative inverse of the divisor
- [tex] = \frac{20o2}{1o5} [/tex]Multiply the fraction
- [tex] = \frac{40}{5} or \: 8[/tex]Simplify
Thus,it requires 8 pouring's of water to fill the 20-liter tank.
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Answer:
- [tex] \frac{40}{5} or \: 8[/tex]
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