Sagot :
Answer:
The domain is x∈(−∞,−1)∪(−1,1)∪(1,∞).
The range is y∈R .
Explanation:
As you cannot divide by
0 , the denominator is ≠0
Therefore,
x2−1≠0
⇒ , (x−1)(x+1)≠0
So, x≠1 and x≠−1
The domain is
x∈(−∞,−1)∪(−1,1)∪(1,∞)
To calculate the range, let
y=3xx2−1
⇒ , y(x2−1)=3x
⇒ , yx2-y=3x
⇒ . yx2−3x−y=0
This ia a quadratic equation in x
and in order to have solutions, the discriminant must be ≥0
Therefore,
Δ=(−3)2−4(y)(−y)≥0
9+4y2≥0
So,
∀y∈R , 9+4y2≥0
The range is
y∈R
graph{3x/(x^2-1) [-18.02, 18.02, -9.01, 9.02]}