Sagot :
✏️QUADRATIC
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1. Solve the quadratic equation by completing the square x² + 4x = 5
- [tex] \sf {x}^{2} + 4x - 5 = 0[/tex]
- [tex] \sf {x}^{2} + 4x = 5[/tex]
- [tex] \begin{gathered} \sf \bigg[ 4 \times \frac{1}{2} \bigg]^{2} = 4 \end{gathered}[/tex]
- [tex] \sf {x}^{2} + 4x + 4 = 5 + 4[/tex]
- [tex] \sf(x + 2)^{2} = 9[/tex]
- [tex] \sf \sqrt{(x + 2)^{2} } = \: ± \: \sqrt{9} [/tex]
- [tex] \sf x + 2 = \: ± \: 3[/tex]
- [tex] \sf x = - 2 \: ± \: 3[/tex]
Solution 1:
- [tex] \sf x = - 2 + 3[/tex]
- [tex] \sf x = 1[/tex]
Solution 2:
- [tex] \sf x = - 2 - 3[/tex]
- [tex] \sf x = -5[/tex]
[tex] \large \therefore\boxed{ \sf{ \green{x = 1,x = - 5}}}[/tex]
[tex] \large \sf [/tex]
2. Solve the quadratic equation by factoring x² + 6x + 9 = 0
- [tex] \sf {x}^{2} + 6x + 9 = 0[/tex]
- [tex] \sf (x + 3)(x + 3) = 0[/tex]
- [tex] \sf x + 3 = 0 \: \: \: \: ; \: \: \: \: x + 3 = 0[/tex]
- [tex] \sf x = - 3 \: \: \: \: ; \: \: \: \: x = - 3[/tex]
[tex] \large \therefore\boxed{ \sf{ \green{x = - 3,x = - 3}}}[/tex]
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Hindi ko po muna ma-eentertain lahat ng messages niyo sa akin. Busy po kasi ako these month and next month. God bless you po.