[tex]\tt{\huge{\red{Solution:}}}[/tex]
[tex]\begin{aligned} \text{mass of fluorine} & = 17.2 \: \cancel{\text{g Mg}} \times \frac{\text{1.563 g F}}{1 \: \cancel{\text{g Mg}}} \\ & = \boxed{\text{26.9 g}} \end{aligned}[/tex]
Hence, the mass of fluorine formed is 26.9 g.
[tex]\\[/tex]
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