[tex]\tt{\huge{\blue{Explanation:}}}[/tex]
The height or position of an object is given by
[tex]\boxed{h = \frac{PE}{mg}}[/tex]
where:
h = height
PE = potential energy
g = acceleration due to gravity = 9.8 m/s²
h = height
[tex]\tt{\huge{\red{Solution:}}}[/tex]
Solving for the height
[tex]h = \dfrac{PE}{mg}[/tex]
[tex]h = \dfrac{\text{14,000 J}}{(\text{40 kg})(\text{9.8 m/}\text{s}^{2})}[/tex]
[tex]\boxed{h = \text{35.71 m}}[/tex]
Therefore, the cannon ball is at the height of 35.71 m.
[tex]\\[/tex]
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