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Find three terms between 2 and 34 of an arithmetic sequence.
solution:​

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Answer:

2, 10, 18, 26, 34

Step-by-step explanation:

An = A1 + (n - 1) d

A5 = 2 + (5 - 1 ) d  

34 = 2 + 4d  

34 - 2 = 4d  

32 = 4d, then divide both sides by 4

8 = d

2 + 8 = 10 (second term)

10 + 8 = 18 (third term)

18 + 8 = 26 (fourth term)

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