how many real roots does the quadratic equation x²-4x+3=0 have?​

Sagot :

Answer:

Explanation:

For the quadratic equation

a

x

2

+

b

x

+

c

=

0

the formula for the roots is

x

=

b

±

b

2

4

a

c

2

a

(

1

)

Identify the values for

a

,

b

,

&

c

x

2

+

4

x

+

3

=

0

cmp

a

x

2

+

b

x

+

c

=

0

a

=

1

b

=

4

c

=

3

(

2

)

Substitute these numbers into eh formula

x

=

4

±

4

2

(

4

×

1

×

3

)

2

×

1

(

3

)

Carefully proceed and do the calculations

x

=

4

±

16

12

2

x

=

4

±

4

2

x

=

4

±

2

2

now calculate the two separate solutions

x

1

=

4

+

2

2

=

2

2

=

1

x

2

=

4

2

2

=

6

2

=

3

Answer:

To find for real roots

b² - 4ac = 0

4² - 4(1)(3)

16 - 12 = 0

4 > 0

so since the discriminant ( b² - 4ac) is greater than zero then there will be 2 real roots.

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