Sagot :
Answer:
Explanation:
For the quadratic equation
a
x
2
+
b
x
+
c
=
0
the formula for the roots is
x
=
−
b
±
√
b
2
−
4
a
c
2
a
(
1
)
Identify the values for
a
,
b
,
&
c
x
2
+
4
x
+
3
=
0
cmp
a
x
2
+
b
x
+
c
=
0
a
=
1
b
=
4
c
=
3
(
2
)
Substitute these numbers into eh formula
x
=
−
4
±
√
4
2
−
(
4
×
1
×
3
)
2
×
1
(
3
)
Carefully proceed and do the calculations
x
=
−
4
±
√
16
−
12
2
x
=
−
4
±
√
4
2
x
=
−
4
±
2
2
now calculate the two separate solutions
x
1
=
−
4
+
2
2
=
−
2
2
=
−
1
x
2
=
−
4
−
2
2
=
−
6
2
=
−
3
Answer:
To find for real roots
b² - 4ac = 0
4² - 4(1)(3)
16 - 12 = 0
4 > 0
so since the discriminant ( b² - 4ac) is greater than zero then there will be 2 real roots.
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