Subtract 2 from both sides of the equation.
x^2+10x=−2
To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of
(b/2)^2 = (5)^2
Add the term to ea
Subtract 2 from both sides of the equation.
x^2+10x=−2
To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of
(b/2)^2 = (5)^2
Add the term to each side of the equation.
x^2+10x+(5)^2=−2+(5)^2
Simplify the equation.
x^2+10x+25=23
Factor the perfect trinomial square into
(x+5)^2•(x+5)^2=23
Solve the equation for x
x=±√23−5
The result can be shown in multiple forms.
Exact Form:
x=±√23−5
