Find the equation of the perpendicular bisector of
the line joining (4,-2) and (-6,-3).


Sagot :

✏️ANSWER

  • [tex]Y = 10x - \frac{25}{2} [/tex]

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✏️SOLUTION

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Write the slope formula.

  • [tex]m = \frac{ {y}^{2} - {y}^{1} }{ {x}^{2} - {x}^{1} } [/tex]

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Subtitute:

  • [tex]m = \frac{ {y}^{2} - {y}^{1} }{ {x}^{2} - {x}^{1} } [/tex]

  • (4, -2), (-6, -3)
  • [tex]m = \frac{ - 3 - ( - 2)}{ - 6 - 4} [/tex]

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Solve the equation.

  • [tex]m = \frac{ - 3 - ( - 2)}{ - 6 - 4} [/tex]
  • [tex]m = \frac{1}{10} [/tex]

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Find the Slope

  • [tex]m = \frac{1}{10} [/tex] Perpendicular.
  • m = -10

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Write the Formula.

  • Write the midpoint formula.
  • [tex] \frac{ x_{1} + x_{2} }{2} \frac{ y_{1} + y_{2}}{2} [/tex]

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Subtitute.

  • [tex] \frac{ x_{1} + x_{2} }{2} \frac{ y_{1} + y_{2}}{2} [/tex]
  • [tex]( \frac{4 - 6}{2} \frac{ - 2 - 3}{2} )[/tex]

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Calculate.

  • [tex] \frac{4 - 6}{2} [/tex]
  • [tex] \frac{ - 2}{2} [/tex]
  • -1

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Calculate.

  • [tex] \frac{ - 2 - 3}{2} [/tex]
  • [tex] \frac{ - 5}{2} [/tex]
  • [tex] - \frac{5}{2} [/tex]

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Rewrite as a coordinates.

  • [tex] - 1 - \frac{5}{2} [/tex]
  • [tex]( - 1 \frac{5}{2} )[/tex]

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Write the equation.

  • Write the equation of linear function.
  • y = mx + b

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Subtitute

  • y = mx + b
  • [tex]m = - 10( - 1 - \frac{5}{2} )[/tex]
  • [tex] - \frac{5}{2} = - 10 \times ( - 1) + b[/tex]

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Solve the equation.

  • [tex] - \frac{5}{2} = - 10 \times ( - 1) + b[/tex]
  • [tex] - \frac{5}{2} = 10 + b[/tex]
  • [tex] - b = 10 + \frac{5}{2} [/tex]
  • [tex] - b = \frac{20 + 5}{ 2} [/tex]
  • [tex] - b = - \frac{25}{2} [/tex]

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Subtitute.

  • y = mx + b
  • [tex]m = - 10, b = - \frac{25}{2} [/tex]
  • [tex]y = 10x - \frac{25}{2} [/tex]

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FINAL ANSWER:

  • [tex]Y = 10x - \frac{25}{2} [/tex]