QUADRATIC EQUATION
Given: x² -10x+25-0 sum of the roots, product of the roots and nature of the roots.
Final answers:
Sum of the roots = 10
Product of the roots = 25
Nature of the roots = Real and equal
Sum of the roots:
[tex] \bold{\frac{ - b}{a}} \\ = \frac{ - ( - 10)}{1} \\ = 10[/tex]
Thus, 10 is the sum of the roots.
Product of the roots:
[tex] \bold {\frac{c}{a} } \\ = \frac{25}{1} \\ = 25[/tex]
Thus, 25 is the product of the roots.
Nature of the roots:
To determine the nature of the roots, let's determine the discriminant first.
[tex] \bold {{b}^{2} - 4ac} \\ {( - 10)}^{2} - 4(1)(25) \\ 100 - 100 \\ 0[/tex]
Thus, 0 is the discriminant and the nature of roots is real and equal.
